Evaluate the integral.

${\displaystyle \underset{0}{\overset{1}{}}}(5+r{)}^{3}dr$

Step $1$

$To$ find $an$ antiderivative $of(5+r{)}^3,we$ will first expand the expression $to$ obtain the following.

$(5+r{)}^3=(\frac{,}{b}ar(125))+(75\frac{75}{15})r+(15)r^2+r^3$

Step $2$

$An$ antiderivative $ofk{x}^n,as$ long $asn-1,is\frac{k()}{n+1}.$