Evaluate the integral

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{10x}{1-x^2\sqrt[\phantom{2}]{1-x^2}}dx$

$-\frac{10}{x}\sqrt[\phantom{2}]{1-x^2}\frac{10}{x}C$

$-10ln(\sqrt[\phantom{2}]{1-x^2}1)C$

$10ln\sqrt[\phantom{2}]{1-x^2}C$

$\frac{10}{2}\sqrt[\phantom{2}]{1-x^2}-\frac{10}{2}C$