Evaluate the integral ${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}6\frac{1}{(16-x^2{)}^{\frac{3}{2}}}dx$

Select one:

a$.\frac{3}{8}\frac{x}{\sqrt[\phantom{2}]{16-x^2}}$

b$.\frac{3}{8}\frac{x}{\sqrt[\phantom{2}]{16-x^2}}C$

c$.\frac{3}{4}\frac{x}{\sqrt[\phantom{2}]{16-x^2}}$

d$.\frac{3}{4}\frac{x}{\sqrt[\phantom{2}]{16-x^2}}C$