Question: Evaluate the integral (by interpreting it as the area between two curves) 1 f |933 a:| da: 1 b Write an integral in the form

 Evaluate the integral (by interpreting it as the area between twocurves) 1 f |933 a:| da: 1 b Write an integral inthe form A = / g(:c) d1; such that A expresses the
area of the region between the functions 3/ = 3:2 2 aand y = 1. Evaluate the integral to nd the area ofthe region. Answers should be exact. As a suggestion, graph the equations

Evaluate the integral (by interpreting it as the area between two curves) 1 f |933 a:| da: 1 b Write an integral in the form A = / g(:c) d1; such that A expresses the area of the region between the functions 3/ = 3:2 2 a and y = 1. Evaluate the integral to nd the area of the region. Answers should be exact. As a suggestion, graph the equations so you can see the region for which you are solving for the area. a (lower limit of integration) = i, b (upper limit of integration) = " 9(w) = I? Area of region A = i, b Write an integral in the form A = / g(:t;) dz; such that A expresses the area of the region between the functions y = m2 and a y = w2 + 650. Evaluate the integral to nd the area of the region. Answers must be exact. As a suggestion, graph the equations so you can see the region for which you are solving for the area. a (lower limit of integration) = y; b (upper limit of integration) = I; 9(16) = #1 Area of region A = y

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