Evaluate the integral.

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{dx}{\sqrt[\phantom{2}]{16x^2-25}},x>\frac{5}{4}$

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{dx}{\sqrt[\phantom{2}]{16x^2-25}}=$

$($Use parentheses to clearly denote the argument of each function.$)$