Evaluate the integral.

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{dx}{\sqrt[\phantom{2}]{36x^2-49}},x>\frac{7}{6}$

Which substitution transforms the given integral info one that can be evaluated directly in terms of $?$

A$.x=\frac{7}{6}sin$

B$.x=\frac{7}{6}tan$

C$.x=\frac{7}{6}sec$