Evaluate the integral or state that it diverges.

${\displaystyle \underset{0}{\overset{}{}}}\frac{16ta{n}^{-1}v}{1v^2}dv$

Select the correct choice below and, if necessary, fill in

A$.{\displaystyle \underset{0}{\overset{}{}}}\frac{16ta{n}^{-1}v}{1v^2}dv=$

$($Type an exact answer in terms of $.)$

B$.$ The integral diverges.