Evaluate the integral

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{x^2}{\sqrt[\phantom{2}]{1x^3}}dx$

using the substitution

$u=1x^3$

$\frac{2}{3}\sqrt[\phantom{2}]{1x^3}C$

$2\sqrt[\phantom{2}]{1x^3}C$

$\frac{2}{3}{x}^3\sqrt[\phantom{2}]{1x^3}C$

$\frac{2}{3}\frac{x^3}{\sqrt[\phantom{2}]{4x{x}^4}}C$