Question: Evaluate the surface integral. *double integral*S y dS S is the surface z =2/3 ( x 3/2 + y 3/2 ), 0 x 1, 0

Evaluate the surface integral. *double integral*S ydS

Sis the surfacez=2/3 (x3/2+y3/2), 0x1, 0y2

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