Question: Evaluating (6-8w)(2w therefore dp = (6-8w)(2w - 3w + 7)dw 3w + 7)dw we make the substitution p = . The integral later transforms
Evaluating (6-8w)(2w therefore dp = (6-8w)(2w - 3w + 7)dw 3w + 7)dw we make the substitution p = . The integral later transforms to -2 / +C. = dp. Hence
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1 68w 2w 3w7 dw Given 2 2 34w 2 w 3w7 dw 25 4w3 2w3w7 dw Now Let 2w ... View full answer
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