Question: Examine the code snippet below. You have to identify the correct snippet for the main and pass each element of the array list = [

Examine the code snippet below. You have to identify the correct snippet for the main and pass each element of the array list=[0,4,1,3] such that for every number less than 2, the error message, "num should be greater than 2", is displayed.
Otherwise, the value returned from the function twice is displayed. What could be the possible solution(s)?
function Myfunc (){
this.twice = function (num){
if (num <2){
throw "num should be greater than 2"
}
return num *2;
}
}
Pick ONE OR MORE options
a)
const myfunc = new Myfunc();
const list = new Array(0,4,1,3);
for (let i =0; i <4; i++){
try {
const res = myfunc.twice(list[i]);
console.log(res);
} catch (e){
console.log(e);
}
}
b)
const myfunc = new Myfunc():
const list ={0,4,1,3};
for (let i =0; i <4; i++){
try {
const res = myfunc.twice(list[i]):
console.log(res);
} catch (e){
console.log(e);
}
}
c)
const myfunc = new Myfunc();
const list =[0,4,1,3];
for (let i =0; i <4; i++){
try {
const res = myfunc.twice(list[i]);
console.log(res);
} catch (e){
console.log(e);
}
}
d)
const myfunc = new Myfunc();
const list =[0,4,1,3];
try {
for (let i =0; i <4; i++){
const res = myfunc.twice(list[i]);
console.log(res);
}
} catch (e){
console.log(e);
}

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