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4G 6:28 PM ...0.6KB/s ll 71 FUN DPP AUG20.... FUN DPP AUG20 SOLVED EXAMPLES EX1. Let f(x)= x² +3x – 2, x21 .Let g(x) be the reflection of the graph of f(x) with respect to the line y=x then g(x)= V17+4x - 3 V17+4x -3 V10-x - 2Vx 21 22 V17+4x – 2 A. 2 В. С. D. SOL.B 8(x)= f (x) 17 f (x) =x² +3x – 2 =| x+ 4 3 25 17 25 17 5 x21=x+ 2 →f(x)22 4 4 4 4 . Rangeoff (x) =[2,00)=f:[1,0)→[2,0) :f :[2,00) →[1,0) y = x' +3x - 2= x +3x-(2+y)=0=x=: -3+ 4y+17 - (y)=s*(x)= -3+ 4x+17 %3D 2 -3+4x+17 :f"(x) =- (i(x)hasrange[1,0) -3+ 4x+17 ::8(x)=- Vxe[2,0) f(x) %3 x(х — 1) {x €R/f"(x) = f(x)} ,00 EX2. If is a function from [ 2 then is (A) null set (В) {1} (C) {0, 2} (D) a set containing 3 elements SOL.C The number of solutiions of J(x) = } (x) is same as number of solutions of (x) = x S(x)=x=x(x-1)=x=x(x-2)=0=x= 0,2 EX3. Solve the equation x -. 1 x + 1 = + 2 4' where x2 4 SOL. 4G 6:28 PM ...0.6KB/s ll 71 FUN DPP AUG20.... FUN DPP AUG20 SOLVED EXAMPLES EX1. Let f(x)= x² +3x – 2, x21 .Let g(x) be the reflection of the graph of f(x) with respect to the line y=x then g(x)= V17+4x - 3 V17+4x -3 V10-x - 2Vx 21 22 V17+4x – 2 A. 2 В. С. D. SOL.B 8(x)= f (x) 17 f (x) =x² +3x – 2 =| x+ 4 3 25 17 25 17 5 x21=x+ 2 →f(x)22 4 4 4 4 . Rangeoff (x) =[2,00)=f:[1,0)→[2,0) :f :[2,00) →[1,0) y = x' +3x - 2= x +3x-(2+y)=0=x=: -3+ 4y+17 - (y)=s*(x)= -3+ 4x+17 %3D 2 -3+4x+17 :f"(x) =- (i(x)hasrange[1,0) -3+ 4x+17 ::8(x)=- Vxe[2,0) f(x) %3 x(х — 1) {x €R/f"(x) = f(x)} ,00 EX2. If is a function from [ 2 then is (A) null set (В) {1} (C) {0, 2} (D) a set containing 3 elements SOL.C The number of solutiions of J(x) = } (x) is same as number of solutions of (x) = x S(x)=x=x(x-1)=x=x(x-2)=0=x= 0,2 EX3. Solve the equation x -. 1 x + 1 = + 2 4' where x2 4 SOL.