Example #712: Hypothesis Test for ne Proportion Using l-PropZTest A researcher who is studying the effects of income levels on breastfeeding of infants hypothesizes that countries where the income level is lower have a higher rate of infant breastfeeding than higher income countries. It is known that in Germany, considered a high-income country by the World Bank, 22% of all babies are breastfeed. In Tajikistan, considered a low-income country by the World Bank, researchers found that in a random sample of 500 new mothers that 125 were breastfeeding their infant. At the 5% level of significance, does this show that more than 22% of all new mothers in Tajikistan breastfeed? Figure #7.2.1: Setup for 1-Proportion Test 1-PropZTest PROPSPO PO Calculate Draw Once you press Calculate, you will see the results as in figure #7.2.2. Figure #7.2.2: Results for 1-Proportion Test 1-PropZTest Prop 22 9575689 1052683219 The sample statistic is the sample proportion, The test statistic is the value of z on the output screen. Z = (p-Po) Po(1-PO) . This means that the observed sample proportion is about the claimed population proportion.6. Obtain the p-value and illustrate the meaning of the p-value, sample statistic and test statistic. . The p-value is the value next to "p", but it is not the value of "p", so make sure you write "p-value =" . p-value = p-value = 0.0527 p: 0.22 0.25 7: 1.62 7. Make a decision about Ho 8. State a conclusion in context