Excess $A{g}_{2}S{O}_4(s)$ is placed in water at some temperature. At equilibrium, the solution contains $3\mathrm{.}88E-2MA{g}^4($aq$).$ What is the equilibrium constant for the reaction below? $A{g}_{2}S{O}_4(s)2A{g}^4(aq)+S{O}_4^{2-}(aq)$

$2\mathrm{.}92$E$-5$

$7\mathrm{.}53$E$-4$

$5\mathrm{.}84$E$-5$

$1\mathrm{.}51$E$-3$

$3\mathrm{.}42E+4$

Mark this question for later review.

Skip to Previous

Skip to Next $$