High fructose corn syrup (HFCS) is a sweetener made from corn syrup (100% Glucose). In a...

  

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High fructose corn syrup (HFCS) is a sweetener made from corn syrup (100% Glucose). In a particular process, that is considered here, the feed (stream1) containing 100% Glucose (G) is mixed with a recycle stream (8) and fed to an isomerization reactor where the glucose (G) is converted to fructose (F). The reaction can be simplified as Glucose -> Fructose The product of the isomerization reaction (Stream 3) contains 42% Fructose. This product stream is split into two, namely streams 4 and 7. Stream 4 is sent to a chromatographic separation unit that results in two product streams (5 and 8). Stream 5 contains 90% Fructose, while stream 8 contains 10% Fructose. Stream 5 is blended with bypass stream 7 in a mixing tank to provide the product HFCS-55 (Stream 6) which contains 55% Fructose. Stream 8 from the chromatographic column is recycled to the isomerization reactor. A particular plant has 100 kg/h of the mixture flowing into the chromatographic unit as shown in the Table. In this problem, the percentages refer to wt %, and we assume that there are just two components, i.e., Fructose and Glucose. Hence a stream containing 30% Glucose implies that the other 70% is Fructose. Questions: 1. Show the appropriate mass balances (for each mass balance, provide the envelope and the equations) and complete the stream table. Showing the envelope around which, a balance is drawn, clearly indicating the species for which a balance is drawn.. 2. What is the per-pass conversion of glucose for the isomerization reactor? 3. What is the overall conversion of glucose for the entire process? 4. What is the extent of the reaction in the isomerisation reactor? 5. Let us say you can directly produce a 55% fructose stream from the separation unit, i.e., you can operate the process in such a way that stream 5 can directly produce 55% fructose. Such an operation will eliminate the need for the bypass stream (stream 7). Which operation mode will you prefer? Provide a short rationale. 8 1 2 Isomerization reactor 3 4 Chromatographic separation 5 Blending 6 7 Stream table showing mass flows in kg/h [ Round up to the nearest 0.1 kg/h] 1 Glucose Fructose Total 2 3 4 5 2 100 6 7 8 High fructose corn syrup (HFCS) is a sweetener made from corn syrup (100% Glucose). In a particular process, that is considered here, the feed (stream1) containing 100% Glucose (G) is mixed with a recycle stream (8) and fed to an isomerization reactor where the glucose (G) is converted to fructose (F). The reaction can be simplified as Glucose -> Fructose The product of the isomerization reaction (Stream 3) contains 42% Fructose. This product stream is split into two, namely streams 4 and 7. Stream 4 is sent to a chromatographic separation unit that results in two product streams (5 and 8). Stream 5 contains 90% Fructose, while stream 8 contains 10% Fructose. Stream 5 is blended with bypass stream 7 in a mixing tank to provide the product HFCS-55 (Stream 6) which contains 55% Fructose. Stream 8 from the chromatographic column is recycled to the isomerization reactor. A particular plant has 100 kg/h of the mixture flowing into the chromatographic unit as shown in the Table. In this problem, the percentages refer to wt %, and we assume that there are just two components, i.e., Fructose and Glucose. Hence a stream containing 30% Glucose implies that the other 70% is Fructose. Questions: 1. Show the appropriate mass balances (for each mass balance, provide the envelope and the equations) and complete the stream table. Showing the envelope around which, a balance is drawn, clearly indicating the species for which a balance is drawn.. 2. What is the per-pass conversion of glucose for the isomerization reactor? 3. What is the overall conversion of glucose for the entire process? 4. What is the extent of the reaction in the isomerisation reactor? 5. Let us say you can directly produce a 55% fructose stream from the separation unit, i.e., you can operate the process in such a way that stream 5 can directly produce 55% fructose. Such an operation will eliminate the need for the bypass stream (stream 7). Which operation mode will you prefer? Provide a short rationale. 8 1 2 Isomerization reactor 3 4 Chromatographic separation 5 Blending 6 7 Stream table showing mass flows in kg/h [ Round up to the nearest 0.1 kg/h] 1 Glucose Fructose Total 2 3 4 5 2 100 6 7 8