Question: Exercise 11.22 in text. .1 5 3 (b).1P, = .5P3 ;.1P= 1P2 ;P+P2 +P3 =1 c) Py = (1/5) P, ; P = P, ;

Exercise 11.22 in text. .1 5 3 (b).1P, = .5P3

Exercise 11.22 in text. .1 5 3 (b).1P, = .5P3 ;.1P= 1P2 ;P+P2 +P3 =1 c) Py = (1/5) P, ; P = P, ; P, - [1 +1 +1/5)= 5/11; What is steady state availability? 0.815 0.909 .951 .755

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