Question: Exercise 2 JULIULUL LU ILLE SIGNAL a : BIT := '1'; SIGNAL b: BIT VECTOR (3 DOWNTO 0) := 1100; SIGNAL C: BIT VECTOR (3

Exercise 2 JULIULUL LU ILLE SIGNAL a : BIT := '1';

Exercise 2 JULIULUL LU ILLE SIGNAL a : BIT := '1'; SIGNAL b: BIT VECTOR (3 DOWNTO 0) := "1100"; SIGNAL C: BIT VECTOR (3 DOWNTO 0) := "0010"; SIGNAL D: BIT VECTOR (7 DOWNTO 0); SIGNAL E: INTEGER RANGE O TO 255; SIGNAL E INTEGER RANGE -128 TO 127; -- Attributes (fill in the blanks) c'LOW -> d'HIGH -> C'LEFT -> d'RIGHT-> c'RANGE -> d' LENGTH -> C'REVERSE_RANGE -> ULILUL Home work: U SIGNAL a : BIT := '1'; SIGNAL : BIT_VECTOR (3 DOWNTO 0) := "1100"; SIGNAL C: BIT_VECTOR (3 DOWNTO 0) := "0010"; SIGNAL D : BIT VECTOR (7 DOWNTO 0); SIGNAL E : INTEGER RANGE O TO 255; SIGNAL f : INTEGER RANGE -128 TO 127; --legal or illegal? b(0) AND a bsra 1 a + d (7) NOT b XNOR C C srl - 2 fror 3 ca e* 3 e - f e IF (b=a) e/3 IF (f/=e) d d) d (6 DOWNTO 3) := b e d'HIGH -> C'LEFT -> d'RIGHT-> c'RANGE -> d' LENGTH -> C'REVERSE_RANGE -> ULILUL Home work: U SIGNAL a : BIT := '1'; SIGNAL : BIT_VECTOR (3 DOWNTO 0) := "1100"; SIGNAL C: BIT_VECTOR (3 DOWNTO 0) := "0010"; SIGNAL D : BIT VECTOR (7 DOWNTO 0); SIGNAL E : INTEGER RANGE O TO 255; SIGNAL f : INTEGER RANGE -128 TO 127; --legal or illegal? b(0) AND a bsra 1 a + d (7) NOT b XNOR C C srl - 2 fror 3 ca e* 3 e - f e IF (b=a) e/3 IF (f/=e) d d) d (6 DOWNTO 3) := b e

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