Question: Exercise 2 M F = 1 = 1 0 0 0 days = > = 1 0 - 3 day ? ( ( ) (

Exercise 2
MF=1=1000 days =>=10-3 day ?(()()-1).
The mean time to failure of a component of a safety system is1000 days. Testing
the component requires 6 hours, whereas the time to repair is negligible.
Please compute the average unavailability of the component, assuming that the
time interval between the end of the previous test and the beginning of the next
one is50 days.
=50 days.
 Exercise 2 MF=1=1000 days =>=10-3 day ?(()()-1). The mean time to

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