Question: Expected Behavior Write a Python class Word that meets the following requirements: Attributes: _word: the string that makes up the word; Methods: __init__(self, word): initializes

Expected Behavior Write a Python class Word that meets the following requirements: Attributes: _word: the string that makes up the word; Methods: __init__(self, word): initializes the _word attribute of the object with the string word supplied as the method's argument. __str__(self): returns the value of the object's _word attribute with all upper-case letters converted to lower-case. A method that takes a Word object other as argument and returns True if other is an anagram of the word, False otherwise. Given two Word objects w1 and w2, it should be possible to determine whether they are anagrams of each other (ignoring upper/lower case differences) using the expression w1 == w2 Note: A word can need not contain just letters. For example, "Hi there! :-)" is a legal word. Examples word1 = Word("post") word2 = Word("stop") word1 == word2 Result: True word1 = Word("") word2 = Word("") word1 == word2 Result: True word1 = Word("aBlE") str(word1) Result: able word1 = Word("able") word2 = Word("baker") word1 == word2 Result: False word1 = Word("Hi there! :-)") word2 = Word("Hit here! :-)") word1 == word2 Result: True

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