Explain how to use patterns or sequences to determine the last digit of the number 7^N, where N is the four-digit year of your birth.

This is what I have: The last digit of where n equals the year of my birth, 1992. Taking the number 7 to apower, the unit digits will repeat after some cycle. Now find the general method to findthe unit digit. The given number is 7^N, whereNis four digit number that we know:

7¹=7

7²=49

7³=343

7⁴=2401

7⁵=16807

7⁶=117649

7⁷=823543

7⁸=5764801

7⁹=40354607

Looking at the sequence above there are four digits that repeats which are: 7, 9, 3,1. However, after the 4th power the unit digits repeats the same sequence. Thispattern can be use to determine the last digits.So if I take my birth year which was 1992. You would divide 1992 by 4 which equals 498. Which means I have no remainder and my remainder would be zero.

1992/4=0

7⁰or7⁴= 1

This is what the evaluation back on this problem was: A repeating pattern of 4 digits was successfully developed using 9 powers of 7 to be 7, 9, 3, 1. It was correctly noted that to find the last digit of 7^1992, the remainder of 1192 divided by 4 should be used. The last digit of 7^1992 was not clearly identified.

How do I fix this so I can pass this task?