Hello,

How would I find 7¹⁹⁸⁷

^{This is as far as I got, but I am not sure how to use the formula}

Explain how to use patterns or sequences to determine the last digit of the number 7^N, where N is the four-digit year of your birth.

After 7⁴,the last digit of the answer repeats every 4 numbers.

7⁴= 2401

7⁵= 16,807

7⁶= 117,649

7⁷= 823,543

7⁸= 5,764,801

7⁹= 40,353,607

7¹⁰=282475249

7¹¹=1977326743

The sequence and pattern can be defined as:

If N = 4n + 1, the last digit is 7.

If N = 4n + 2, the last digit is 9.

If N = 4n + 3, the last digit is 3.

If N = 4n, the last digit is 1.

Since the last digit of my year of birth (1987) is 7, then the sequence and pattern is defined as N=4n + 1...