explain solution in depth An alternative approach casts uses lim

x$0$

sin x

x

$=1$ by making the denominator match the

argument of the trigonometric function:

lim

$0$

sin$(2$$)$

$5$

$=1$

$5$ lim

$0$

sin$(2$$)$

$2$

$(2)$

$=$

$($x$=2$$)2$

$5$ lim

x$0$

sin x

x

$=2$

$5(1)=2$

$5$