Question: Explain that for the function f(x, y) = xy, of x :(1,1) = Dif(1,1) = 1 but for the function g(y, x) = yx2,

Explain that for the function f(x, y) = xy, of x :(1,1) = Dif(1,1) = 1 but for the function g(y, x) = yx2, 3x -(1,1) = D2g(1,1) = 2. Also check that f = g.
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