Explain this code in C

#include int a (int x) { if(x)

//what does it mean when we say this, does it mean if the variable x has a 1 in it then return 1?, but how? we didn't even say [ if(x==1) ]?? return 1; return 1; else return 0; } int b(int x) { if(!x | x) //Also here, please explain how is this condition understood by the compiler? return 1; else return 0; } int main() { int x; printf(\"Input:\"); scanf(\"%d\",&x); printf(\" %d\",a(x)); printf(\" %d\",b(x)); return 0; }