Question: explain to me how the answer is .891. 4) Find the probability of at least 2 girls in 6 births. Assume that male and female
explain to me how the answer is .891.
4) Find the probability of at least 2 girls in 6 births. Assume that male and female births are equally .901 by 04/ D 4 ) likely and that the births are independent events. Define X= Chance of at least z girls out of 6 births P (x2 2 ) = 1- P (x(2) = 1- binomedf ( 6,. 5, 2) A) 0.656 B) 0.234 C) 0.109 D) 0.891 ts and uses this acceptance sampling plan: 5 ) BStep by Step Solution
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