Extra Credit (+10 pts): Rouse derived an exact expression for the stress relaxation modulus: G(t)=kBTNb3p=1Nexp(t/p) where the relaxation time of mode p is given by: p=62kBTb2(pN)2 Starting from this expression, show that for the application of an oscillatory strain that varies as: (t)=0exp(it) that the Boltzmann superposition principle yields: G()=0(t)=G()+iG() where G()=kBTNb3p=1N1+(p)2(p)2 and G()=kBTNb3p=1N1+(p)2(p) Recall that the Boltzmann superposition principle states that: (t)=iG(tti)i=iG(tti)iti There is no partial credit for this