F: For the following transfer function

$\frac{s+2}{2s^2+6s+50}$

and desired pole locations of $s_{1,2}=-1+-j3,$ the angle deficiency is equal to $f=127.$ When designing a lead compensator using the following method

it is found that after bisecting angle between lines PA and PO the bisected angles are insufficient to accommodate $\frac{f}{2}$ on each side of the bisector. The best solution to this problem is to

increase the gain of the lead compensator.

cascade a lag compensator with the first lead compensator.

design a lag compensator.

use feedforward control.

cascade a second lead compensator with the first lead compensator.