F$($inflow$)$ CH$4100\%16\mathrm{.}0$ kg Air$($inflow$)$ A $=500$ kg$($mol $\%)021\mathrm{.}0$ N$279\mathrm{.}0$ P$($outflow$)?$kg CO$2=?$ N$2=?02=?$ H$20=?$ Solve P and each mole composition using $($a$)$the element balance method and $($b$)$ the specific balance method. In F$,$ the number of moles of CH$4$ is obtained by calculating the number of moles of $02$ and N$2$ at $1$ A$.$If $3\mathrm{.}2($C$2$H$4)+02-->2($C$2$H$40)50$ kmol of C$2$H$4$ and $50$ kmol of $02$ are added,$($a$)$ what is the limiting reactant? $($b$)$ If the reaction is completed, how many moles of C$2$H$40$ are made $+$ what is the extent of reaction at this time? $($d$)$ if the reaction is made up to $30\%$ of the limiting reactant, what is the amount of each of the last generated$/$ remaining? $($e$)$ When $30$ kmol of $02$ remains after the reaction, what is the fraction of C$2$H$4$ and $02?$ What is the extent of reaction at this time?