Question: f ( x ) = sqrt ( 8 - 2 x ) , what is f ^ ( ' ) ( x ) ?

f(x)=\sqrt(8-2x), what is f^(')(x)?
f^(')(x)=(-1)/((8-2x)^(-0.5))
f^(')(x)=-(1)/(\sqrt(8-2x))
f^(')(x)=(1)/(2\sqrt(8-2x))
f^(')(x)=(-2)/((8-2x)^(-0.5))
f ( x ) = \ sqrt ( 8 - 2 x ) , what is f ^ ( ' )

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Mathematics Questions!