$f(x)=\frac{x^3-7x+2}{4x}$

How would you rewrite $f(x)$ so it can be differentiated using the product rule?

Assume $x0.$

Choose $1$ answer:

$\frac{x^2}{4}-\frac{7}{4}+\frac{1}{2x}$

$\frac{x^3}{4x}-\frac{7x}{4x}+\frac{2}{4x}$

$\frac{1}{4}{x}^{-1}(x^3-7x+2)$

This is not possible.