Question: Figure 1.8 shows the conventional inverting amplifier configuration with a 10k? load resistor at the output. R1 Vin 1KQ NJ 741 0 Vout AWG1 10KQ

AWG1 10KQ Figure 1.8 Inverting amplifier configurationsD 6.32 Design the circuit in

Figure 1.8 shows the conventional inverting amplifier configuration with a 10k? "load" resistor at the output. R1 Vin 1KQ NJ 741 0 Vout AWG1 10KQ Figure 1.8 Inverting amplifier configurationsD 6.32 Design the circuit in Fig. P6.32 to establish a current of 0.5 mA in the emitter and a voltage of -0.5 V at the collector. The transistor UEB = 0.64 V at IF = 0.1 mA, and B = 100. To what value can Re be increased while the collector current remains unchanged? +2.5 V RE RC -2.5 V Figure P6.321. For the full wave rectifier of Figure 4-4. If C= 330 UF, RL = 510 0, Vin=12VRMS @60 Hz and each diode's forward voltage drop is 0.7 volts, calculate a. Ripple frequency, fr b. Peak output voltage Vp (This is not the sinusoidal input voltage's peak.) c. Peak-to-peak ripple voltage, Vr d. Load current, IL (A good approximation is obtained by neglecting ripple.) e. Average diode current, IDav f. Maximum diode current, IDmax

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