Fill in and answer the colored cells

\begin{tabular}{|c|c|c|c|} \hline A & B & C & D \\ \hline \multicolumn{4}{|l|}{ Newsvendor Model } \\ \hline & & & Demand \\ \hline \multirow{2}{*}{ Data } & & & 1 \\ \hline & & & 2 \\ \hline \multirow{3}{*}{\multicolumn{2}{|c|}{\begin{tabular}{r} Selling price \\ Cost \\ Discount price \end{tabular}}} & & 3 \\ \hline & & & 4 \\ \hline & & & 5 \\ \hline & & & 6 \\ \hline \multirow{2}{*}{ Model } & & & 7 \\ \hline & & & 8 \\ \hline \multirow{3}{*}{\begin{tabular}{r} Demand \\ Purchase Quantity \end{tabular}} & & & 9 \\ \hline & & & 10 \\ \hline & & & 11 \\ \hline \multirow{5}{*}{\begin{tabular}{r} Quantity Sold \\ Surplus Quantity \\ \end{tabular}} & & & 12 \\ \hline & & & 13 \\ \hline & & & 14 \\ \hline & & & 15 \\ \hline & & & 16 \\ \hline Total Cost & & & 17 \\ \hline \multirow{2}{*}{\begin{tabular}{l} Total Cost \\ Total sales revenue \\ Total salvage value \end{tabular}} & & & 18 \\ \hline & & & 19 \\ \hline \multirow[t]{11}{*}{ Profit } & & & 20 \\ \hline & & & 21 \\ \hline & & & 22 \\ \hline & & & 23 \\ \hline & & & 24 \\ \hline & & & 25 \\ \hline & & & 26 \\ \hline & & & 27 \\ \hline & & & 28 \\ \hline & & & 29 \\ \hline & & & 30 \\ \hline \end{tabular} Hint: You should set up a Newsvendor model similar to the above example, and then use a one-way data table in the highlighted area to figure out the profit for variaous demand. The lowest demand at which the profit turns positive is the answer you are \begin{tabular}{|c|c|c|c|} \hline A & B & C & D \\ \hline \multicolumn{4}{|l|}{ Newsvendor Model } \\ \hline & & & Demand \\ \hline \multirow{2}{*}{ Data } & & & 1 \\ \hline & & & 2 \\ \hline \multirow{3}{*}{\multicolumn{2}{|c|}{\begin{tabular}{r} Selling price \\ Cost \\ Discount price \end{tabular}}} & & 3 \\ \hline & & & 4 \\ \hline & & & 5 \\ \hline & & & 6 \\ \hline \multirow{2}{*}{ Model } & & & 7 \\ \hline & & & 8 \\ \hline \multirow{3}{*}{\begin{tabular}{r} Demand \\ Purchase Quantity \end{tabular}} & & & 9 \\ \hline & & & 10 \\ \hline & & & 11 \\ \hline \multirow{5}{*}{\begin{tabular}{r} Quantity Sold \\ Surplus Quantity \\ \end{tabular}} & & & 12 \\ \hline & & & 13 \\ \hline & & & 14 \\ \hline & & & 15 \\ \hline & & & 16 \\ \hline Total Cost & & & 17 \\ \hline \multirow{2}{*}{\begin{tabular}{l} Total Cost \\ Total sales revenue \\ Total salvage value \end{tabular}} & & & 18 \\ \hline & & & 19 \\ \hline \multirow[t]{11}{*}{ Profit } & & & 20 \\ \hline & & & 21 \\ \hline & & & 22 \\ \hline & & & 23 \\ \hline & & & 24 \\ \hline & & & 25 \\ \hline & & & 26 \\ \hline & & & 27 \\ \hline & & & 28 \\ \hline & & & 29 \\ \hline & & & 30 \\ \hline \end{tabular} Hint: You should set up a Newsvendor model similar to the above example, and then use a one-way data table in the highlighted area to figure out the profit for variaous demand. The lowest demand at which the profit turns positive is the answer you are