Fill in the missing blanks and answer this question completely step by step. The following integral describes the volume of the solid of revolution. Describe the solid. \pi\int_{0}^{\frac{\pi}{2}}\sin^{2}{(x)}\,dx The integral \pi\int_{0}^{\frac{\pi}{2}}\sin^{2}{(x)}\,dx=\pi\int_{0}^{\frac{\pi}{2}}\left(\boxed{?} ight)^2\,dx describes the volume of the solid obtained by rotating the region R=\left\{(x,y)|0\leq \boxed{?}\leq \frac{\pi}{2},0\leq \boxed{?}\leq \sin{(x)} ight\} of the xy-plane about the \boxed{?}