Find an equation of a function that meets the given conditions.

$x-$intercepts: $(4,0)$ and $(2,0)$

vertical asymptote: $x=-2$

horizontal asymptote: $y=1$

$y-$intercept: $(0,2)$

Choose the equation that meets the given conditions.

$f(x)=\frac{x^2-6x+8}{x^2+4x+4}$

$f(x)=\frac{x^2+6x+8}{x^2+4x+4}$

$x^2-6x+8$