Find

${\displaystyle \underset{C}{\overset{\phantom{}}{}}}(8$yvec$(i)+4$zvec$(j)+5$xvec$(k))*dvec(r)$

where $Cis$ the boundary $of$ the triangle with vertices $(5,0,0),(0,4,0),$

$(-5,0,0),$ traversed $in$ that order.

Enter $an$ exact answer.

${\displaystyle \underset{C}{\overset{\phantom{}}{}}}$vec$(F)*dvec(r)=$