Find $\frac{d^3}{d{x}^3}(x^{2}lnx)$

$\frac{d^3}{d{x}^3}(x^{2}lnx)=\frac{1}{x}$

$\frac{d^3}{d{x}^3}(x^{2}lnx)=\frac{6}{x^4}$

$\frac{d^3}{d{x}^3}(x^{2}lnx)=\frac{2}{x}$

$\frac{d^3}{d{x}^3}(x^{2}lnx)=\frac{6}{x^2}$

$\frac{d^3}{d{x}^3}(x^{2}lnx)=\frac{3}{x^4}$