Question: Find dy/dx for following curves & evaluate at given points e^x + ln(y) = 1 point: (0,1) My answer: y' = y(1-e^x) x^2 + y^

Find dy/dx for following curves & evaluate at given points

e^x + ln(y) = 1 point: (0,1)

My answer: y' = y(1-e^x)

x^2 + y^ 4 - xy^2 = 1 Points: (0,1) (1,-1)

my answer: y'= -2x^4 + y + 1/ 4y^4 - 2xy

don't understand what the points are for, just for checking?

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