Find the center, foci, and vertices of the ellipse. Graph the equation. 36x + 360x +...

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Find the center, foci, and vertices of the ellipse. Graph the equation. 36x² + 360x + 16y²-96y +468 = 0 36 (x²+ 10x) + 16 (²-6y) = - 468 Use the complete the square process to convert the given ellipse to standard form 36 (x² +10x) + 16 (y²-6y) - Standard form: = - 468 The center of the ellipses is located at The distance to the vertices, a = The focal length, c = (Simplify if needed) The main avie of the allinea is narallel to the Lavie The value of b = Find the center, foci, and vertices of the ellipse. Graph the equation. 36x² + 360x + 16y²-96y +468 = 0 36 (x²+ 10x) + 16 (²-6y) = - 468 Use the complete the square process to convert the given ellipse to standard form 36 (x² +10x) + 16 (y²-6y) - Standard form: = - 468 The center of the ellipses is located at The distance to the vertices, a = The focal length, c = (Simplify if needed) The main avie of the allinea is narallel to the Lavie The value of b =

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Answer I Also a 6 b 3 c sqrta 2 b 2 sqrt36 9 519615242 the major ax... View the full answer