Find the derivative of the function by using the product rule. Then, multiply out the function and find the derivative by treating the function as a polynomial. Compare the results. V=(h^3-7)(4h^2-4h-2)

n 4 Of 15 This question: 6 point(s) possib Find the derivative of the function by using the product rule. Then multiply out the function and find the derivative by treating the function as a polynomial. Compare the results. V= (13 -7) (42 - 41-2) which of ine following snows ine result Of using the product rule to Tina Ine derivative of Ine given Tunction? OA. (412 - 41- 2) an (412 - 4n -2) - (13 -7) an (13-7) ( 1 3 - 7) 2 O B. (412 - 41-2) an (13 - 7) - (13 -7) an (412 - 41-2) ( 1 3 - 7) 2 O c. (n3 - 7) an (n3 - 7) + (4n2 - 41-2) an (412 - 41-2) OD. (n3 -7) on (an2 - an -2) + (4n2 - 41-2) an (13 - 7) The derivative using the product rule is V' =]. Multiplying the function out results in the polynomial (Simplify your answer. Do not factor.) The derivative of the polynomial is V' =] Compare the results. Choose the correct answer below. A. The derivatives found by both methods are the same. O B. The derivatives found by both methods are different and unrelated. O C. The derivatives found by both methods are negative inverses. O D. A derivative can always be found more quickly by applying the derivative of a product formula than by first multiplying the factors and then differentiating.V = ( h 3 - 7 )( 4 b 2 - 4 h - 2 ) Product rule : I five ) . gex) = fix,d gag V = (8 3 - 7 ) ( ub 2 - uh - 2 product rule : I flay. gray = floyd gray + gray of fury for this question Derivative using product rule V' = (h 3 - 7 ) 8 ( 46 2 - 4 h- 2) + (4/2-4h - 2 ) 2 ( h 3 -7 ) option D is correct .= h3 - 7 1 8 h - 4 ) + 4h2 - 4 - 2 ) (3 /2 = 8 hi - uh3 - 2 64 - 28+ 1267 - 12h - oh2 = 2 0 h 4 - 16 6 3 - 6 6 2 - 56h+ 28 multiplication of function (h 3 - 7 ( 4 6 2 - 4 h - 2 ) 4 hs - 4hy - 2 6 3 - 28 h 2 + 28h + 14 Derivative of polynomial N' = d uh5 - 464 - 263 - 2862 + 28h+lu V ' = 20 hy - 16 63 - 6 h2 - 56+28 - option A: Derivature found by both Me thod are Same