Question: Find the equation for the plane through Po ( - 6,8,8) perpendicular to the following line. x= -6+t, y= 8 + 4t, z=5t, - co

Find the equation for the plane through Po ( - 6,8,8)

perpendicular to the following line. x= -6+t, y= 8 + 4t, z=5t,

Find the equation for the plane through Po ( - 6,8,8) perpendicular to the following line. x= -6+t, y= 8 + 4t, z=5t, - co

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