Find the general solution of the given differential equation. (0 - cos + c) (0 - sin 0 + c) sec +tan ( 1 1 A. r = sec -tan 1 B. r = C. r = D. r = E. None sec (cos + c) 1 sec 0+tan 0 (0 - cos 0 + c) D O B OE dr +r sec0: = cos 0 do Find the solution of the given initial value problem in explicit form. Also, determine the interval in which the solution is defined, y' = xy (1 + x) , y (0) = 1 A. y = the solution is defined when |x| 5 = -21+ B. y = C. y = D. y = E. None -2v [32 -21+x2 1 21+2 D O B E the solution is defined when |x| > 5 the solution is defined when |x| < the solution is defined when x < 5