Find the indefinite integral ${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{2x+1}{x^2+1}dx.$

$2ln(x^2+1)-ta{n}^{-1}x+C$

$ln(x^2+1)+ta{n}^{-1}x+C$

$\frac{ln(x^2+1)}{2}+ta{n}^{-1}x+C$

$ln(x^2+1)+C$

$x^2+ta{n}^{-1}x+C$