Question: Find the integrating factor, the general solution, and the particular solution satisfying the initial condition. y' - 4y = - 2e 21; y(0) = -

Find the integrating factor, the general solution, and the particular solution satisfying the initial condition. y' - 4y = - 2e 21; y(0) = - 1 .. . O A. The integrating factor is e - 4t. O B. The integrating factor is e 4t The general solution is y = - e - 21 + Ce 4t The general solution is y = - 2t + Ce 4t The particular solution is y = - e - 21 - 2 e 4t The particular solution is y = - 2t- e 4t O.C. The integrating factor is e - 4t O D. The integrating factor is e 4t. The general solution is y = e 2t + Ce 4t The particular solution is y = e 2t - 2 4t. The general solution is y = 1 6t + Ce 4t 4 The particular solution is y = 6t - 4t 3
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