Find the reference number for each value of $t.$

$($a$)t=\frac{4}{3}$

$$

$($b$)t=\frac{5}{3}$

$$

$\frac{}{3}$

You got itt

$($c$)t=-\frac{7}{6}$

$$

$($d$)t=3\mathrm{.}3$

$$

Enter an exact answer with no rounding.