Question: Find the six trigonometric ratios in exact form for angle 0 = 3150. Answer as a reduced fraction/radical. cos 3150 = sec 3150 = O

$= 3150. Answer as a reduced fraction/radical. cos 3150 = sec 3150$

Find the six trigonometric ratios in exact form for angle 0 = 3150. Answer as a reduced fraction/radical. cos 3150 = sec 3150 = O N/ - V2 2V/3 3 0 12 0 2 sin 3150 = csc 3150 = O - 2 V2 O _ V3 2 O _ 2V3 3 0 -V2 0 -2 tan 3150 = cot 3150 = O _ V3 3 0 -1 0 -V3 O _ 13 3 0 -1 0 - V3

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