Find the work function for each case using

E_max=E_photonW

where E_max=e|V| for a stopping voltage V . The vertical bars mean "absolute value", e.g. remove the sign.

Give a work function for each case, and explain your work.

Additional info:

We are working with wavelengths of:

1) 365nm

2) 405 nm

3) 436 nm

4) 546 nm

The energy in electron volts of each are as follows:

By using E = (h*c/e*wavelength) you can find the energy of the electron volts for the photons of each of the 4 wavelengths that we used.

E = 6.626 x 10^-34 * 3 * 10^8/1.6x10^-19 x 365 x 10^-9

365 nm = 3.399 eV

E = 6.626 x 10^-34 * 3 * 10^8/1.6x10^-19 x 405 x 10^-9

405 nm = 3.068 eV

E = 6.626 x 10^-34 * 3 * 10^8/1.6x10^-19 x 436 x 10^-9

436 nm = 2.845 eV

E = 6.626 x 10^-34 * 3 * 10^8/1.6x10^-19 x 546 x 10^-9

546 nm = 2.27 eV

The applied voltage for each stopped at:

365 nm was -01.82

405 nm was -01.44

436 nm was -01.29

546 nm was -00.70