Find using matlab:
You can use symbollic math to make it easier if you'd like. And please keep in mind to create all of this in ONE GRAPH and not subplots as shown in the picture. Mind the interval as well since lambda is supposed to be not equal to 0 and 90. Please make sure the code works and is showing the plot that's in the question before submitting. Otherwise I will downvote if its not the same^

Transcribed Image Text:

The efficiency, in percent, of a power screw when the friction of the collar is ignored, is given by the following equation: e = 100 - cos(a) μ tan(A) cos(a) +μcot(A) % where u is the coefficient of friction, λ is the lead angle of the screw, and a is the thread angle. Plot the efficiency e (on the y-axis) versus the lead angle 2 (on the x-axis), for the following values: - - - 0<<90° u =0.02, 0.05, 0.10, 0.15, 0.20 and 0.25 a for two thread angles: a = 7° and α = 14.5° Label the figure and the individual curves. The results should look like those shown in the figure below. Efficiency of a power screw 100 μ=0.02 90 =0.05 80 =0.1 70 70 =0.15 = 0.2 60 =0.25 50 Efficiency (%) 40 30 20 10 0 ° = thread angle 14.5° -thread angle = 7° 10 20 30 40 50 60 70 80 80 Lead angle (degrees) 20 90 The efficiency, in percent, of a power screw when the friction of the collar is ignored, is given by the following equation: e = 100 - cos(a) μ tan(A) cos(a) +μcot(A) % where u is the coefficient of friction, λ is the lead angle of the screw, and a is the thread angle. Plot the efficiency e (on the y-axis) versus the lead angle 2 (on the x-axis), for the following values: - - - 0<<90° u =0.02, 0.05, 0.10, 0.15, 0.20 and 0.25 a for two thread angles: a = 7° and α = 14.5° Label the figure and the individual curves. The results should look like those shown in the figure below. Efficiency of a power screw 100 μ=0.02 90 =0.05 80 =0.1 70 70 =0.15 = 0.2 60 =0.25 50 Efficiency (%) 40 30 20 10 0 ° = thread angle 14.5° -thread angle = 7° 10 20 30 40 50 60 70 80 80 Lead angle (degrees) 20 90

Answer rating: 100% (QA)

Sure I can help you with the prompt in the image but I cannot display or directly reference the imag... View the full answer