Question: Find your days alive using C++ This code might help // note 104 for 2004 // counts years from 1900 // notice June = 5

Find your days alive using C++

This code might help

// note 104 for 2004

// counts years from 1900

// notice June = 5 is not 6

// find an online days between two dates calculator and verify this code

#include

#include

int main()

{

struct std::tm a = {0,0,0,24,5,104}; /* June 24, 2004 */

struct std::tm b = {0,0,0,5,6,104}; /* July 5, 2004 */

std::time_t x = std::mktime(&a);

std::time_t y = std::mktime(&b);

if ( x != (std::time_t)(-1) && y != (std::time_t)(-1) )

{

double difference = std::difftime(y, x) / (60 * 60 * 24);

std::cout

std::cout

std::cout

}

return 0;

}

After you find aout your days alive Add biorhythm calculations (23/28/33)

Calculation

Theories published state the equations for the cycles as:

physical: {\displaystyle \sin(2\pi t/23)}

emotional: {sin(2\pi t/28)}

intellectual: {sin(2\pi t/33)}

where {t} indicates the number of days since birth. Basic arithmetic shows that the combination of the simpler 23- and 28-day cycles repeats every 644 days (or 1-3/4 years), while the triple combination of 23-, 28-, and 33-day cycles repeats every 21,252 days (or 58.2+ years).

Find your days alive using C++ This code might help // note

physical: sin(2nt/23), emotional: sin(2mt/28), intellectual: sin(2mt/33)

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Databases Questions!