\fn = 4.02 . 10-3 [kg.m-1.5-1], R = 3.5 . 10-6 [m], pp = 1097 [kg.m-3], Pm = 1023 [kg.m-3], - a = 6.4 x 10-6 w = 126 [rad.5-1] rotating frame 7 x* V FS Fg XO inertial frame 4 X a =; (Pp - Pm)R3 w = 6.4 x 10-6 aw aw * * 2(1 +a2) 2(1 +a2). 2 Yotl to aw dx* Y* 2 dt 1= x0 (exp (2 to) - 1) Xo Vplasma = d2 xo (exp ( 2 to) - 1) a = on ( Pp - Pm) R3 wcentrifugation", derive the analytical expression for vy, starting from the law of motion in the rotating frame of reference: -banRU+3 (Pp - Pm)Rag -3 (Pp - Pm) R3(20 x d' + a x (@XF))=0 (You must produce a step-by-step derivation of the analytical expression to receive full credit.) [5 points] Where in the tube the velocity, v, is highest? [5 points] What would happen if density of the cell was lower than that of the suspending medium