For any real number $x,$ positive or negative, $\sqrt[3]{x}$ denotes the real cube root of $x.$ Often we use $x****(\frac{1}{3})$ to compute $\sqrt[3]{x}$ in Python, but when $x$ is negative this will give the wrong answer. For example, the real cube root of $-1$ is $-1,$ but if you type

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Python $3$

$(-1)*****(\frac{1}{3})$

Python will compute $0\mathrm{.}5000000000000001+0\mathrm{.}8660254037844386j,$ a complex cube root of $-1.($Python uses $1+2j$ to denote the complex number $1+2$i where $i^2=-1).$

Write a Python function real$\_$cube$\_$root $(x)$ which returns a real cube root of any real number $x.$

Answer that will be automatically graded below, ID: $04$a$3$d$6$

$($A$)]$ Explain

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$6$

In $[3]$: def real$\_$cube$\_$root$($x$)$:

input: a real number $x,$ positive, negative, or zero.

output: a real cube root of $x$